16x^2-25/4x+5

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Solution for 16x^2-25/4x+5 equation: 


x in (-oo:+oo)

16*x^2-((25/4)*x)+5 = 0

16*x^2+(-25/4)*x+5 = 0

16*x^2-25/4*x+5 = 0

DELTA = (-25/4)^2-(4*5*16)

DELTA = -4495/16

DELTA < 0

x belongs to the empty set

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